There is an old saying from my days in college. When one is fixated on a completely false idea, it is impossible to argue with invincible ignorance. Let him believe in himself and move on.
I'm moving on.
I made it *really* simple. Not so much for you, because I think you are shilling for ball-Earth, rather than genuinely trying to understand. But for anyone honest that reads your posts and for whatever reason believes you might be right.
https://www.quora.com/What-is-the-range-of-an-average-marine-radar-on-US-Navy-ships?share=1
"Almost every one of the 50+ US Navy ships I sailed on had an installed “average marine radar” from a manufacturer like Raytheon or Furuno. These tend to be “fishing boat” radars with ranges of 25 to 75 nm, depending on how high above the sea surface they were installed."
Note that 25 nautical miles (the lower estimate given) is approximately 46km.
View attachment 248033
● Let A, B and E represent 3 ships, of height H1, H2, H3, on a ball-Earth of circumference C and radius r.
● Let ships A and B be located on the ball-Earth at such a distance that a straight line between the highest point on A and the highest point on B is tangent with ball-Earth. [This sets ship B at the maximum possible detectable distance, by straight line, from A].
● Let T represent the point where the tangent line AB intersects the ball-Earth.
● Let O represent the center of ball-Earth.
● Let ϴ1 represent the angle between OA and OT.
● Let ϴ2 represent the angle between OT and OB.
● Let ϴT represent the sum of the angles ϴ1 and ϴ2.
● Let D represent the distance of the arc along the circumference of ball-Earth, between the ships A and B.
Also, let:
● H1 = 10m
● H2 = 10m
● C = 40,075,017m
● r = 6,378,000m
Then:
● From basic trigonometry, we know that cos(ϴ) = Adjacent/Hypotenuse
cos (ϴ1) = r / (r + H1)
cos (ϴ1) = 0.999998432112838
cos (ϴ2) = r / (r + H2)
cos (ϴ2) = 0.999998432112838
ϴ1 = acos(0.999998432112838)
ϴ1 = 0.00177081200133473 radians
ϴ2 = acos(0.999998432112838)
ϴ2 = 0.00177081200133473 radians
● We also know that 360º = 2π radians
ϴ1 = 0.001770812 * 360 / (2.π)
ϴ1 = 0.101460053987595º
ϴ2 = 0.001770812 * 360 / (2.π)
ϴ2 = 0.101460053987595º
ϴT = ϴ1 + ϴ2
ϴT = 0.10146º + 0.10146º
ϴT = 0.20292º
● There are 360º in a circle.
D = ϴT / 360 * C
D = 0.20292º / 360º * 40,075,017m
D = 22588.951249m
D = 22.59km
● Therefore, if we lived on a ball-Earth of circumference C = 40,075km, the maximum range that a straight‑beam radar mounted 10m above sea-level could detect a 10m-high ship, is 22.59km.
● In reality, radar can detect ships at much greater distances than this (e.g. easily at 50km).
● The trigonometric diagram of ball-Earth, together with radar ranges which greatly exceed the maximum range predicted by the ball-Earth model, therefore demonstrate that we do not live on a ball‑Earth at all, as some would have us imagine.
There is an old saying from my days in college. When one is fixated on a completely false idea, it is impossible to argue with invincible ignorance. Let him believe in himself and move on.
I'm moving on.
I guessed right! What you call ionosphere, is what concave hollow earthers call, glass sky. Tomato/Tamata. I heard a story about radio signals being picked up in other countries in Europe, and that's why some people believed in the glass sky way back when. youtube stuff
Good luck changing a flat earther's mind! lol
The ionosphere can re-radiate electromagnetic waves. This property is used by over the horizon radars. It has nothing to do with glass. It is possible to detect high frequency radio transmissions by the same ionospheric re-radiation. You need a decent HF receiver for reliable reception.
FE people? None so blind...................
Keep the videos coming, Concave Hollow Earth is looking rock solid!
Once my experiment is done and it checks out like these videos, and the survey done 200 years ago by the U.S. Government in Florida, I will officially state, flat earth, and convex earth has been proven false. Tick tock!
So.....excited!
By the way, those guys using lasers like that, are completely irresponsible. They should be arrested, but that's just my opinion.
There is an old saying from my days in college. When one is fixated on a completely false idea, it is impossible to argue with invincible ignorance. Let him believe in himself and move on.
I'm moving on.
Happy to help. I'm rusty on this, so it won't be overly comprehensive.Can you please explain this further, since I honestly don't understand. If the ionosphere is not solid glass/ice, than how do radio waves bounce off a non-solid surface?
Thanks for explaining, if you do answer my question.
Happy to help. I'm rusty on this, so it won't be overly comprehensive.
The ionosphere, as the name suggests, is the region where solar radiation (UV and X-ray)ionises the upper regions of the atmosphere. This enables radio waves to re-radiate from the layer and so allows the lower frequencies to bounce off the ionosphere. That's the simple answer.
https://www.swpc.noaa.gov/phenomena/ionosphere
If you look at the diagram, you will see that if the frequency is high enough, it will pass through the ionosphere. This is why super high frequency radars have short range. They cannot bounce off the ionosphere. They are not able to follow the curvature of the earth. The higher frequencies are required to give enough definition to a target to track it. Low frequency radars have much longer ranges but are unable to provide enough data to allow a lock on the target. Stealth aircraft are not invisible to all radar frequencies. They are near invisible to radars that are suitable to guide missiles to a target. Modern missiles have built in seekers, radar and/or Infra red, to overcome the limitations of long range radar. Once the missile is near enough, the inbuilt seekers take over and the target has to defend itself. Easier said than done.
Happy to help. I'm rusty on this, so it won't be overly comprehensive.
The ionosphere, as the name suggests, is the region where solar radiation (UV and X-ray)ionises the upper regions of the atmosphere. This enables radio waves to re-radiate from the layer and so allows the lower frequencies to bounce off the ionosphere. That's the simple answer.
https://www.swpc.noaa.gov/phenomena/ionosphere
If you look at the diagram, you will see that if the frequency is high enough, it will pass through the ionosphere. This is why super high frequency radars have short range. They cannot bounce off the ionosphere. They are not able to follow the curvature of the earth. The higher frequencies are required to give enough definition to a target to track it. Low frequency radars have much longer ranges but are unable to provide enough data to allow a lock on the target. Stealth aircraft are not invisible to all radar frequencies. They are near invisible to radars that are suitable to guide missiles to a target. Modern missiles have built in seekers, radar and/or Infra red, to overcome the limitations of long range radar. Once the missile is near enough, the inbuilt seekers take over and the target has to defend itself. Easier said than done.
I guess I'm dumb, I still don't understand. lol Can you work with me? I want to understand your view here.
Um. Yeah, so radio waves bounce off of an ionizes atmosphere?!?! I get that bit, but what gets ionized?
Can you please explain this atmosphere? Is it made out of Jello? Air? Ether? What? I'm gonna need some information, because ionizing atmosphere doesn't really answer my question. Forget the ionizing bit, what is this atmosphere you speak of? Please go into depth on this atmosphere that gets ionized.
I guess I'm dumb, I still don't understand. lol Can you work with me? I want to understand your view here.
Um. Yeah, so radio waves bounce off of an ionizes atmosphere?!?! I get that bit, but what gets ionized?
Can you please explain this atmosphere? Is it made out of Jello? Air? Ether? What? I'm gonna need some information, because ionizing atmosphere doesn't really answer my question. Forget the ionizing bit, what is this atmosphere you speak of? Please go into depth on this atmosphere that gets ionized.
https://scied.ucar.edu/learning-zone/atmosphere/layers-earths-atmosphere
No doubt you know that the atmosphere, i.e. air, is less dense as it rises above sea level. It took me a couple of days to get used to the thinner air at the Grand Canyon. Climbers take oxygen with them to the summit of Everest.
So yes, it's air, which I am breathing right now. To be more precise,
"Nitrogen and oxygen are by far the most common gases in Earth's atmosphere. Dry air is composed of about 78% nitrogen (N2) and about 21% oxygen (O2). The remaining less than 1% of the atmosphere is a mixture of gases, including Argon (Ar) and carbon dioxide (CO2). The atmosphere also contains varying amounts of water vapor, on average about 1%. There are also many, tiny, solid or liquid particles, called aerosols, in the atmosphere. Aerosols can be made of dust, spores and pollen, salt from sea spray, volcanic ash, smoke, and pollutants introduced through human activity."

If it was glass, it should have been well and truly shattered by now. Hundreds of people would have died by crashing into the glass. Not a lot of logic in what you believe. I'll stick to empirical observations from people who have been up there.
If it was glass, it should have been well and truly shattered by now. Hundreds of people would have died by crashing into the glass. Not a lot of logic in what you believe. I'll stick to empirical observations from people who have been up there.