you didn't even read the page you linked, eh?
it contains no proof, nor even a definition of 'most irrational'
what it states about convergent subseries is true for any integer multiple of phi -- therefore ((as previously intimated)) there are infinitely many irrational numbers with equally poor convergent approximations.
you don't know what you're talking about, and to people who do, you look dumber every time you bring it up.
it contains no proof, nor even a definition of 'most irrational'
what it states about convergent subseries is true for any integer multiple of phi -- therefore ((as previously intimated)) there are infinitely many irrational numbers with equally poor convergent approximations.
you don't know what you're talking about, and to people who do, you look dumber every time you bring it up.
φ is irrational
2φ is irrational
3φ is irrational
4φ is irrational
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nφ is irrational for any integer n
one of φ's infinite series representations when truncated poorly approximates φ
one of 2φ's infinite series representations when truncated poorly approximates 2φ
one of 3φ's infinite series representations when truncated poorly approximates 3φ
one of 4φ's infinite series representations when truncated poorly approximates 4φ
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.
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one of nφ's infinite series representations when truncated poorly approximates nφ, for any integer n
which member of this infinite set each with equally poor truncated infinite series representation approximations is "most irrational" ??
define 'most irrational' please.
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